Search: https://www.galaxus.ch/en/sector/showdiscussion/snapchathacking-visit-kunghaccom-5hflaboo-226168
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| BP45 |
| Outline figure on top of solid black figure vs. black figure on top of outline figure. |
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REFERENCE
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M. M. Bongard, Pattern Recognition, Spartan Books, 1970, p. 228. |
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CROSSREFS
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Adjacent-numbered pages:
BP40 BP41 BP42 BP43 BP44  *  BP46 BP47 BP48 BP49 BP50
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KEYWORD
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dual, finished, traditional, viceversa, bongard
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CONCEPT
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3d_front_back (info | search), outlined_filled (info | search), objects_overlap (info | search), overlap (info | search), texture (info | search)
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AUTHOR
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Mikhail M. Bongard
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| BP934 |
| If "distance" is taken to be the sum of horizontal and vertical distances between points, the 3 points are equidistant from each other vs. not so. |
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COMMENTS
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In other words, we take the distance between points (a,b) and (c,d) to be equal to |c-a| + |d-b|, or, in other words, the distance of the shortest path between points that travels along grid lines. In mathematics, this way of measuring distance is called the 'taxicab' or 'Manhattan' metric. The points on the left hand side form equilateral triangles in this metric.
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An alternate (albeit more convoluted) solution that someone may arrive at for this Problem is as follows: The triangles formed by the points on the left have some two points diagonal to each other (in the sense of bishops in chess), and considering the corresponding edge as their base, they also have an equal height. However, this was proven to be equivalent to the Manhattan distance answer by Sridhar Ramesh. Here is the proof:
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An equilateral triangle amounts to points A, B, and C such that B and C lie on a circle of some radius centered at A, and the chord from B to C is as long as this radius.
A Manhattan circle of radius R is a turned square, ♢, where the Manhattan distance between any two points on opposite sides is 2R, and the Manhattan distance between any two points on adjacent sides is the larger distance from one of those points to the corner connecting those sides. Thus, to get two of these points to have Manhattan distance R, one of them must be a midpoint of one side of the ♢ (thus, bishop-diagonal from its center) and the other can then be any point on an adjacent side of the ♢ making an acute triangle with the aforementioned midpoint and center. |
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CROSSREFS
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Adjacent-numbered pages:
BP929 BP930 BP931 BP932 BP933  *  BP935 BP936 BP937 BP938 BP939
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KEYWORD
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hard, allsorted, solved, left-finite, right-finite, perfect, pixelperfect, unorderedtriplet, finishedexamples
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CONCEPT
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triangle (info | search)
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WORLD
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3_dots_on_square_grid [smaller | same | bigger]
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AUTHOR
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Leo Crabbe
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| BP1233 |
| Different curves cross each other vs. curves only cross themselves (or do not cross at all). |
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| BP952 |
| Images of Bongard Problems about images of Bongard Problems about images of Bongard Problems vs. images of Bongard Problems not including images of Bongard Problems including images of Bongard Problems. |
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| BP368 |
| There is a point that can see (in straight lines) all points vs. there is no point that can see (in straight lines) all points. |
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| BP128 |
| Same objects inside and outside the large shape vs. not same objects inside and outside the large shape. |
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| BP198 |
| Stays in vs. escapes. |
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| BP106 |
| Negative slope vs. positive slope. |
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| BP44 |
| Small circles on different arcs vs. small circles on one arc. |
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| BP79 |
| A dark circle is closer to the outline circle than to the triangle vs. a dark circle is closer to the triangle than to the outline circle. |
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REFERENCE
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M. M. Bongard, Pattern Recognition, Spartan Books, 1970, p. 240. |
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CROSSREFS
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Adjacent-numbered pages:
BP74 BP75 BP76 BP77 BP78  *  BP80 BP81 BP82 BP83 BP84
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KEYWORD
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spectrum, finished, traditional, continuous, viceversa, bongard
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CONCEPT
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length_line_or_curve (info | search), near_far (info | search), outlined_filled (info | search), texture (info | search), triangle (info | search)
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AUTHOR
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Mikhail M. Bongard
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